求解几个C语言的题
6.#include stdio.h
main()
{
float xiaoshou,shouru;
printf("benzhouxiaoshouzongewei:"袭蚂仔);
scanf("%f",xiaoshou) ;
shouru=200+xiaoshou*0.08;
printf("benzhoushouruwei:%f\n",shouru);
getch();
}
7.
#include stdio.h
void main()
{
float principal,rate,days,interest;
printf("qingshurubenjin:");
scanf("%f"拍汪,principal) ;
printf("qingshurulilv:");
scanf("%f",rate) ;
printf("qingshurutianshu:");
scanf("%f",days) ;
interest= principal*rate*days/365;
printf("lixiwei:%f",interest);
getch();
}
8.1 :end
8.2:*
9:
#include stdio.h
main()
{ int year;
printf("qing shu ru nian fen:");
scanf("%d",year);
if( ((year%4==0)(year%100!=0)) ||(year%400==0) )
printf("%d nian shi run nian.",year);
else
printf("%d nian bu shi run nian",year);
getch();
}
14.1 : i=9 , j%3!=0 (注意是不等于,不是等于)
14.2:p=p+j s=s+p;
16:(备物则注:输出的结果非常多,因为组合方法很多。)
#include stdio.h
main()
{ int gongji,muji,xiaoji,n;
for(gongji=0;gongji=20;gongji++)
{
for(muji=0;muji=33;muji++)
{
for(xiaoji=0;xiaoji=300;xiaoji++)
{
if(5*gongji+3*muji+xiaoji/3==100) ;
printf("%dzhi gongji,%dzhi muji, %dzhi xiaoji\n",gongji,muji,xiaoji);
}
}
}
getch();
}
17:#include stdio.h
main()
{
int i,a,b,c;
for(i=100;i1000;i++)
{
a=i/100;
b=(i-a*100)/10;
c=i-a*100-b*10;
if(i==a*a*a+b*b*b+c*c*c)
{
printf("%d\n",i);
}
}
getch();
}
18:
#include stdio.h
main()
{
int wufen,yimao,c=0;
for(wufen=1;wufen=10;wufen++)
{
for(yimao=1;yimao=5;yimao++)
{
if(wufen/2+yimao==5)
c++;
}
}
printf("yi gong you %d zhong huan fa",c);
getch();
}
19:
#include stdio.h
void main()
{
int a[20];
int i;
int min;
printf("qing shu ru 20 ge shuzi:");
for(i=0;i20;i++)
scanf("%d",a[i]);
min=a[0];
for(i=1;i20;i++)
{
if(mina[i]) min=a[i];
}
printf("zui xiao de shuzi shi :%d\n",min);
getch();
}
22:#include stdio.h
#include math.h
int ss(int m)
{
int i,t1=0,q;
q=sqrt(m);
for (i=2;i=q;i++)
if (m%i==0)
break;
if (i=q+1)
t1=1;
return(t1);
}
void main()
{
int i,t=0,sum=0;
for (i=100;i=200;i++)
{
t=ss(i);
if (t==1)
sum+=i ;
}
printf("%d",sum);
getch();
}
10:
#include stdio.h
main ( )
{ long i;
float bonus,bon1,bon2,bon4,bon6,bon10;
bon1=100000*0.1;
bon2=bon1+100000*0.075;
bon4=bon2+100000*0.05;
bon6=bon4+100000*0.03;
bon10=bon6+400000*0.015;
printf("qing shu ru li run:");
scanf("%ld",i);
if (i=100000)
bonus=i*0.1;
else if (i=200000)
bonus=bon1+(i-100000)*0.075;
else if (i=400000)
bonus=bon2+(i-200000)*0.05;
else if (i=600000)
bonus=bon4+(i-400000)*0.03;
else if (i=1000000)
bonus=bon6+(i-600000)*0.015;
else bonus=bon10+(i-1000000)*0.01;
printf("jiang jin shi %10.2f",bonus);
getch();
}
第9题前面已经有了,重复了,你自己看。
程序全部验证通过,这么辛苦,给分吧。
请教C语言编程中计算还贷后剩余的贷款金额的详细答案, 最好能够说明一下每个步骤!
#include stdio.h
int main(void){
float amount,rate,payment,month_rate,tmp1,tmp2,tmp3;
指伏 printf("Enter amount of lean:");
scanf("%f",amount);
printf("Enter interest rate:");
scanf("%f",rate);
printf("Enter monthly payment:");
scanf("%f",payment);
month_rate = rate / 100.0f / 12.0f;
卖逗派 tmp1 = (amount-payment)+amount*month_rate;
tmp2 = (tmp1-payment)+tmp1*month_rate;
tmp3 = (tmp2-payment)+tmp2*month_rate;
printf("Balance remaining after first payment:%.2f\n",tmp1);
printf("Balance remaining after second payment:%.2f\n",tmp2);
printf("Balance remaining after third payment:%.2f\n",tmp3);
}
这是我的答案,我觉得最佳答案对于学习第一章的朋友并不中贺是很友好。
求贷款利率c语言的介绍就聊到这里吧,感谢你花时间阅读本站内容,更多关于c语言贷款计算、求贷款利率c语言的信息您可以在本站进行搜索查找阅读喔。
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