贷款利息计算器的代码是什么？

c语言 银行贷款的月利率 简单代码

#include stdio.h

#includemath.h

main()

{

 double money,capital;

 double rate[4]={0.009,0.01,0.0111,0.012};

 int n;

 printf("请输入本金和期限(年)\n");

 scanf("%lf%d",capital,n);

 if(n3)

  money=capital*pow((1+rate[3]),12*n);

 else

  money=capital*pow((1+rate[n-1]),12*n);

 printf("%d年后本金和利息合计为：%.2lf\n",n,money); 

}

C++ C语言程序设计 题目：贷款计算器

/*

* main.c

*

* Created on: 2011-6-8

* Author: icelights

*/

#include stdio.h

#include stdlib.h

#include ctype.h

#include math.h

#define APR1 0.0747 /*1年（含1年）年利率*/

#define APR2 0.0756 /*1-3年（含3年）年利率*/

#define APR3 0.0774 /*3-5年（含5年）年利率*/

#define APR4 0.0783 /*5年以上年利率*/

#define A_TO_M 1/12 /*月利率 = 年利率 / 12*/

#define RTP 12 /*Reimbursement total periods还款总期数 =年限*12*/

#define LENGTH 80

struct LoanInfo

{

/*姓名*/

char name[LENGTH];

/*贷款总额*/

double LoanAmount;

/*贷款年限*/

double LoanYear;

/*月付*/

double MonthlyPayment;

/*总利息*/

double TotalInterest;

/*还款总额*/

double ReimbursementAmount;

/*年利率*/

double apr;

struct LoanInfo * next;

};

void CalcShow(struct LoanInfo * cur, struct LoanInfo * hd,

struct LoanInfo * prv);

int main(void)

{

int temp;

struct LoanInfo * head = NULL;

struct LoanInfo * prev, * current;

current = (struct LoanInfo *)malloc(sizeof(struct LoanInfo));

if (NULL == head)

{

head = current;

}

else

{

prev-next = current;

}/*End of if (NULL == head)*/

puts("请输入姓名");

gets(current-name);

fflush(stdin);

puts("请输入贷款数额（单位：万元）");

scanf("%lf", ¤t-LoanAmount);

fflush(stdin);

puts("请输入贷款年限");

scanf("%lf", ¤t-LoanYear);

fflush(stdin);

printf("姓名：%s,贷款年限：%lf, 贷款数额%lf",

current-name, current-LoanYear, current-LoanAmount);

prev = current;

puts("请确认Y/N");

temp = getchar();

switch(toupper(temp))

{

case 'Y' : CalcShow(current, head, prev);

break;

case 'N' : free(current);

main();

break;

default : puts("输入错误");

free(current);

break;

}

return 0;

}

void CalcShow(struct LoanInfo * cur, struct LoanInfo * hd,

struct LoanInfo * prv)

{

char lcv_temp;

if (cur-LoanYear = 1)

cur-apr = APR1;

else if (cur-LoanYear = 3)

cur-apr = APR2;

else if (cur-LoanYear = 5)

cur-apr = APR3;

else

cur-apr = APR4;

/*End of if (year = 1)*/

cur-LoanAmount = 10000 * cur-LoanAmount;

cur-ReimbursementAmount = cur-LoanAmount * pow((1 + cur-apr), cur-LoanYear);

cur-MonthlyPayment = cur-ReimbursementAmount / (cur-LoanYear * RTP);

cur-TotalInterest = cur-ReimbursementAmount - cur-LoanAmount;

printf("姓名：%s 贷款年限：%.0lf\n"

"贷款数额：%.2lf 每月还款额：%.2lf\n"

"利息合计：%.2lf 还款总额：%.2lf\n",

cur-name, cur-LoanYear, cur-LoanAmount,

cur-MonthlyPayment, cur-TotalInterest, cur-ReimbursementAmount);

puts("是否继续计算Y/N");

lcv_temp = getchar();

switch(toupper(lcv_temp))

{

case 'Y' : free(cur);

main();

break;

case 'N' : free(cur);

exit(0);

default : puts("输入错误");

free(cur);

main();

break;

}

system("pause");

}

有关银行贷款还贷的c语言程序

你的错误实在太多了。看代码王的程序简洁易懂

#includestdio.h

#includemath.h

int main()

{

double z,k,x,monthPay,allMoney,temp=0;

int n,i;

printf("输入借款总额、贷款年限、年利率: ");

//贷款总和最好不要用int型的，int的最大值是32767，那你岂不是超了

scanf("%lf%d%lf",z,n,k);

//计算n年后要还的总的钱数 pow(x,y)是在头文件math.h中的函数计算x^y

allMoney = z*pow((1+k/12),12*n);

//式子∑x(1+k/12)^i （i=0,1,2,..,n*12-1）将x提出到前面计算 temp=∑(1+k/12)^i

for(i=0; i12*n; i++)

temp += pow((1+k/12),i);

//根据等式z(1+k/12)^(12*n) = ∑x(1+k/12)^i （i=0,1,2,..,n*12-1） 得x=allMoney/temp;

x = allMoney/temp;

printf("每月应还款：%lf", x);

}

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